Answer:
Na₂SO₄
Explanation:
Assume that you have 100 g of the compound.
Then you have 32.37 g Na, 22.57 g S, and 45.05 g O.
1. Calculate the moles of each element.
Moles of Na = 32.37 × 1/22.99 = 1.408 mol Na
Moles of S = 22.57 × 1/32.06 = 0.7040 mol S
Moles of O = 45.05 × 1/16.00 = 2.816 mol O
2. Calculate the <em>molar ratio</em>s.
Divide all values by the smallest number.
Na: 1.408/0.7040 = 2.000
S: 0.7040/0.7040 = 1
O: 2.816/0.7040 = 4.000
3. Determine the empirical formula
Round off all numbers to the closest integer.
Na: 2
S: 1
O: 4
The empirical formula is Na₂SO₄.
Answer:
Explanation:
Ionic (or electrovalent) compounds conduct electricity when there they are in the aqueous state/solution because the charges of ions of these compounds are what carry the electric charges in the aqueous solution as a result of free movement within the aqueous solution which they do not "have" when in there solid state (where they have a highly restricted movement/compacted structure).
Answer: The net change in the atoms is the conversion of a neutron to a proton, turning Carbon (6 protons) into Nitrogen (7 protons).
Explanation:
Carbon-14, generated from the atmosphere, has 6 protons and 8 neutrons. That's where the 14 comes from, called the mass number, is the sum of protons and neutrons (6+8=14).
Carbon-14 is radioactive and decays by beta decay. That means one of its neutrons spontaneously turns into a proton, an electron, and a neutrino, according to:
After that, the atom has 7 protons and 7 neutrons, maintaining its mass number but changing its atomic number from 6 to 7, turning into Nitrogen.
Answer:
German chemist G.E. Stahl
This is a neutralisation reaction, so we know that the products formed are salt and water.
First, we balance the chemical equation:
KOH + HNO3 ----> KNO3 + H2O.
After that, we split the compounds into their respective charges.
K+ + OH- + H+ + NO3- ----------> K+ + NO3- + H2O*
(*note that liquid cannpt be splitted.)
After that we reduce the chemical equation by removing the common ones.
OH- + H+ --------> H2O
Tada.