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kompoz [17]
3 years ago
12

Calculate the wavelength of a radio wave with a frequency of 93.1 x 10^6 ^-1

Chemistry
2 answers:
gulaghasi [49]3 years ago
7 0
Wave speed = frequency x wavelength

therefore wavelength = wave speed / frequency

the speed of radio waves ( and all electromagnetic waves in vacuum) is 3 x 10^8 meters per second

just put the numbers in now ☺
melomori [17]3 years ago
6 0

Answer:  3.22 m

Explanation:

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave =93.1\times 10^6s^{-1}

c = speed of light =3\times 10^8ms^{-1}

\lambda = wavelength of the wave

Now put all the given values in this formula, we get

\lambda=\frac{3\times 10^8ms^{-1}}{93.1\times 10^6s^{-1}}

\lambda=3.22m

Thus wavelength of a radio wave with a frequency of 93.1\times 10^6s^{-1} is 3.22 m.

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How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant
schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

  • 1 g = 1,000 mg
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The time  that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s

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3 years ago
The partial negative charge at one end of a water molecule is attracted to the partial positive
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             Hydrogen Bond

Explanation:

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6 0
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At constant temperature a bicycle tire pump contains 252mL of air at 995kPa pressure. The plunger of the pump is pushed down unt
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Answer:

The new pressure of the pump is 26.05 atm or 2639.4 kPa

Explanation:

Step 1: Data given

Volume of the bicycle tire pump = 252 mL = 0.252 L

Pressure of air = 995 kPa = 9.81989 atm

The volume of the pump is reduced to 95.0 mL = 0.095 L

Step 2: Calculate the new pressure

V1*P1 = V2*P2

⇒with V1 = the initial volume of the bicycle tire pump = 0.252 L

⇒with P1 = the initial pressure of the pump = 9.81989 atm = 995 kPa

⇒with V2 = the reduced volume of the pump = 0.095 L

⇒with P2 = the new pressure = TO BE DETERMINED

0.252 L * 9.81989 atm = 0.095 L * P2

P2 = 26.05 atm

The new pressure is 26.05 atm

OR

0.252 L * 995 = 0.095 L * P2

P2 = 2639.4 kPa

The new pressure of the pump is 26.05 atm or 2639.4 kPa

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3 years ago
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