Answer:
in a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.
Explanation:
the attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other.
Ecell = E°cell - RT/vF * lnQ
R is the gas constant: 8.3145 J/Kmol
T is the temperature in kelvin: 273.15K = 0°C, 25°C = 298.15K
v is the amount of electrons, which in your example seems to be six (I'm not totally sure)
F is the Faradays constant: 96485 J/Vmol (not sure about the mol)
Q is the concentration of products divided by the concentration of reactants, in which we ignore pure solids and liquids: [Mg2+]³ / [Fe3+]²
Standard conditions is 1 mol, at 298.15K and 1 atm
To find E°cell, you have to look up the reduction potensials of Fe3+ and Mg2+, and solve like this:
E°cell = cathode - anode
Cathode is where the reduction happens, so that would be the element that recieves electrons. Anode is where the oxidation happens, so that would be the element that donates electrons. In your example Fe3+ recieves electrons, and should be considered as cathode in the equation above.
When you have found E°cell, you can just solve with the numbers I gave you.
This would be a supersaturated solution!
Answer:
1u1u2j2jj and her family
Explanation:
I have been 9in 7the 6same 6of 8for and then I am a solicitor at Cardiff on
The answer is the first one!!! have a WONDERFUL day!!
