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Katen [24]
2 years ago
7

Hi y’all please help me !

Mathematics
2 answers:
mestny [16]2 years ago
6 0

Answer:

C

Step-by-step explanation:

They are vertical angles, vertical angles always have the same measurement. example below

this angle is 56---> 56 ><m <---- this angle is always 56 since they are vertical

Helga [31]2 years ago
4 0
C

Explanation:
They are both equal on both sides, meaning if one is 11 the other is 11
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Carmen predicted in a read a thon mr.cole pledged $4.00per book and gave carmen 44$. how many books did carmen read
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11

11 times 4 equals 44

8 0
3 years ago
Please help with these two questions thank you.
prohojiy [21]
1. Perpendicular Transverse Theorem
2. a=30 and b=60
6 0
3 years ago
The shapes below are mathematically similar.
Lera25 [3.4K]

Answer:

Triangle small ABC

Triangle big DEF

AB = 8 cm , BC = 12 cm , DE = 20 cm , EF = x

So;

\frac{AB}{DE} =  \frac{BC}{EF}  \\  \\  \frac{8}{20} =  \frac{12}{x}   \\  \\ 8x = 12 \times 20 \\ 8x = 240 \\  \\ x =  \frac{240}{8}  \\  \\ x = 30 cm

I hope I helped you^_^

7 0
2 years ago
Bob rode his scooter 2.3 miles to his friend's house, then 0.8 miles to the library, then 1.9 miles to the grocery store. If he
Stella [2.4K]

Answer:

add all of these mesurements together 2.3 + 0.8 + 1.9 then  do it times 2

the awnser is 10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

\frac{20}{9}x-\frac{20}{3}

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
2 years ago
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