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Sholpan [36]
2 years ago
15

67. The line contains the point (4,0) and is parallel to the line defined by 3x = 2y.

Mathematics
1 answer:
olganol [36]2 years ago
7 0

Answer:

y=\frac{3}{2} x-6

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:
  • y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

3x = 2y

Switch the sides

2y=3x

Divide both sides by 2 to isolate y

\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x

Now that this equation is in slope-intercept form, we can easily identify that \frac{3}{2} is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope \frac{3}{2} . Plug this into y=mx+b:

y=\frac{3}{2} x+b

<u>2) Determine the y-intercept</u>

y=\frac{3}{2} x+b

Plug in the given point, (4,0)

0=\frac{3}{2} (4)+b\\0=6+b

Subtract both sides by 6

0-6=6+b-6\\-6=b

Therefore, -6 is the y-intercept of the line. Plug this into y=\frac{3}{2} x+b as b:

y=\frac{3}{2} x-6

I hope this helps!

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