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Kipish [7]
3 years ago
5

Study the sentences below. A.Changing the properties of characters in a sentence or paragraph in a Word document helps increase

the document’s readability. B.Changing the properties of characters in a sentence or paragraph in a Word document helps increase the document’s READABILITY. Which properties of the word "readability” changed? Check all that apply. case color font size style
Computers and Technology
2 answers:
anastassius [24]3 years ago
7 0

Answer:

The Space Between the lines both paragraphs

decreased

Explanation:

if you're using edgenuity you already know why your're here also i got it right just by having it up. this is the first result you get for this question.

identifying Changes in Paragraph Layout

Original PassageChanged Passage

Study the original and changed passages.

Original passage:

One way to make a document more readable is by controlling the space between paragraphs, which can be done by adding space between and after a paragraph.

Another way to make a document more readable is by keeping the paragraph on one page, which can be done by changing the spaces between the lines in the paragraph.

Which change was applied to the original paragraph?

The space between the lines of both paragraphs increased.

The space between the lines of both paragraphs decreased.

The space between paragraphs 1 and 2 increased.

The space between paragraphs 1 and 2 decreased.

Andru [333]3 years ago
4 0

Answer:

Case

Explanation:

Given

A. "...document’s readability."

B. "...document’s READABILITY"

Required:

Which properties of the word "readability” changed?

Questions like this are best supported with attachments

Because of the way your question is presented, it's impossible to state if there's a change in color, font size and font style.

However, I'll answer your question based on what's obvious.

The texts "readability" and "READABILITY" have different casing;

readability is a lowercase text while READABILITY is an uppercase text.

The above analysis answers what's obvious regarding your question.

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Answer:

C. 14.4 kwhr.

Explanation:

To calculate the energy used by appliance first calculate the power. The formulae for calculating power(<em>P</em>) is P= I \times V, where V stands for voltage and I stands for current.

In the given problem,  V = 240 volts and I = 15 amp. Therefore,

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Now, formulae for calculating energy used i.e. work(W) is W = P\times t, where <em>t</em> is the time.

In the given question time is 4 hr. Therefore energy used will be,

Energy used (W) = 3.6\times4 =14.4\ kwhr.

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