Answer:
a. A only
Explanation:
When air, is in excess of allowable amounts, it can cause the system to operate at pressures that are higher than normal. This means that the recycled refrigerant is operating at high pressure. Thus Technician A is correct.
However, Technician B is incorrect because unlike reclaimed refrigerants where the process strip the refrigerant of impurities making it to meet the standards of a new refrigerant, the recycled refrigerant is not as pure as it's contaminants are only reduced.
Therefore, only technician A is correct.
Answer:
The answer is "Option ".
Explanation:
The SOA stands for "Service-Oriented Architecture", which is primarily known as a service set and these services enable you to communicate with each other. In the communication, it may require simple data to transfer to two or more services, which can be organized by those operations, and other options were incorrect, that can be explained as follows:
- In option a, It is a business software, which is used to organized data, that's why it is wrong.
- Option b and Option d both are wrong because the mashup process is used only on web services, which is not a part of SOA , that's why it is wrong.
Answer: 9.5%
Explanation: There were nearly 5 million English language learners in U.S. public schools in fall 2015, according to the most recent available data from the National Center for Education Statistics. This represented 9.5% of U.S. public school enrollees, an increase from 8.1% in 2000
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
