A] David's speed during the period:
i] AB
speed=distance/time
time taken between AB=0.5 hours
distance=20 km
thus
speed=20/0.5=40 km/h
ii]BC
time taken between BC=1.5 hours
distance=20
speed=20/1.5=13 1/3 km/h
b] Average speed for the entire time will be:
average speed=(total distance)/(total time)
total distance=(20+20+20)=60 km
total time=3 hours
thus
average speed=60/3=20 km/h
c] David's distance 2 hours and 15 minutes from the starting point was:
distance=20+20+10=50 km
X can be a value of any number less than 0.9.
Solved, this is x<1 as an inequality.
Answer:
15
Step-by-step explanation: 5/2= 2.5
6·2.5= 15
i hope this helps lol
3y = 4
First, take the 3 and divide both sides by it.

Answer as fraction:

Answer as decimal: 1.3333
Answer:
The maximum number of days is 5
Step-by-step explanation:
Let
x ----> the number of days
y ---> the total cost to rent a car in dollars
we know that
The fixed rental fee plus the daily fee multiplied by the number of days must be less than or equal to Pasion's budget
so
The inequality that represent this situation is

Solve the inequality for x
Subtract 25 both sides
Divide by 10 both sides

therefore
The maximum number of days is 5