All categories

2 years ago

Clasifica los documentos comerciales en activo, pasivo o patrimonial para cada operacion:

Computers and Technology

1 answer:

julia-pushkina [17]2 years ago

6 0

Answer:

I wish I could answer your question, but I believe that is no English.

Explanation:

You might be interested in

Channel logging tokens can be set to all but:________. a. Relaxed b. Strict c. Both versions d. None

Rudik [331]

Answer:

c. Both versions

Explanation:

The Windows Remote management has hardening levels that could be set to Relaxed, Strict, or None based on the channel binding token associated with a request. This feature could be automatically found in the system or manually configured to a user's choice.

Relaxed settings mean rejection of channel binding token that are not valid and the acceptance of requests with no channel binding tokens, but which may be susceptible to attacks. Strict settings entail an automatic rejection of invalid channel binding tokens. None settings entail the acceptance of all requests with no protection against credential-forwarding attacks.

4 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Write one for loop to print out each element of the list several things. then write another for loop

Kay [80]

Question:

Write one for loop to print out each element of the list several_things. Then, write another for loop to print out the TYPE of each element of the list several_things.

Answer:

The solution in python is as follows:

for element in several_things:

print(element)

for element in several_things:

print(type(element))

Explanation:

The solution assumes that the list several_things has already been initialized.

So, the rest of the code is explained as follows:

This line iterates through the list, several_things

for element in several_things:

This line prints each element

print(element)

This line iterates through the list, several_things for the second time

for element in several_things:

This line prints the type of each element

print(type(element))

6 0

2 years ago

Jim has listed stages of the product life cycle in his presentation which slide element can you use to make the items in the lis

IgorC [24]

jim can use bullet points.

this
is
an
example
of
bullet
points!

8 0

2 years ago

The operation of early electronic computing devices required:

Harrizon [31]

Answer:

Explanation:

5 0

2 years ago