Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
Answer:
False.
Explanation:
When we declare a variable as reference type we have to initialize that variable otherwise the compiler will give error that the reference variable is not initialized.You also cannot initialize the variable Foo& with NULL value because it is a reference variable and we have to initialize it.
On the other there is no need to initialize the variable Foo * since it is a pointer it can also store NULL value.
So the answer is only Foo* can store NULL value not Foo &.
Answer:
Not all people but sometimes it happens
Answer:
That would be (d) All of these. I hope this helps you!
