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3 years ago

I WILL GIVE A BRAIN LIST TO THE FIRST PERSON WHO ANSWERS!!!!!!!

Mathematics

2 answers:

aksik [14]3 years ago

6 0

Answer:

its c

Step-by-step explanation:

Our denominators are 40 and 4. What we need to do is find the lowest common denominator of the two numbers. This is the smallest number that can be divided by both 40 and 4. In this case, the lowest common denominator is 40.

If we multiply the first denominator (40) by 1 we will get 40. If we multiply the second denominator (4) by 10 we will also get 40. We also need to multiply the numerators above the line by the same amounts so that the fraction values are correct:

33 x 1

40 x 1

3 x 10

4 x 10

This is what 33/40 and 3/4 looks like with the same denominator:

33

30

Now that these fractions have been converted to have the same denominator, we can clearly see by looking at the numerators that 33 is greater than 30 which also means that 33/40 is greater than 3/4.

Yuki888 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

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Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$