Answer:
huh
Step-by-step explanation:
11 is the answer
hope this helps
Answer:
90° is correct answer. :)
Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Given that,
The given expression is : ![16x^0+2x^2{\cdot}y^{-1}](https://tex.z-dn.net/?f=16x%5E0%2B2x%5E2%7B%5Ccdot%7Dy%5E%7B-1%7D)
To find,
The value of the above expression when x = 2 and y = 4
Solution,
We have,
![16x^0+2x^2{\cdot}y^{-1}](https://tex.z-dn.net/?f=16x%5E0%2B2x%5E2%7B%5Ccdot%7Dy%5E%7B-1%7D)
Put x = 2 and y = 4 in the above expression.
![16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18](https://tex.z-dn.net/?f=16x%5E0%2B2x%5E2%7B%5Ccdot%7Dy%5E%7B-1%7D%5C%5C%5C%5C%3D16%5Ctimes%20%282%29%5E0%2B2%282%29%5E2%5Ctimes%20%284%29%5E%7B-1%7D%5C%5C%5C%5C%3D16%5Ctimes%201%2B2%282%29%5E2%5Ctimes%5Cdfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%3D16%2B2%5C%5C%5C%5C%3D18)
So, the value of the above expression is 18.