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yulyashka [42]
3 years ago
8

Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equ

ation. x² + 4x = 15 2x(x−3)=0 A. square root property B. zero product property C. completing the square
Mathematics
1 answer:
NemiM [27]3 years ago
7 0
For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.

For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.

For the second equation, since it is already factored, we use the zero product property to solve it.
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To replace a number with another number that tells how many or how much
Papessa [141]
It's subtraction or multiplacation
8 0
3 years ago
Michael Jordan scores the following points over 8 games: 24, 17, 28, 19, 23, 20, 13, 19. What is the mean (average) number of po
olga nikolaevna [1]

Answer:

19

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
400 ml squash is made by mixing 50 ml of cordial with water. what fraction of the drink is water?give your answer in its simples
Tasya [4]

squash = cordial + water

400 ml = 50 ml + x ml

350 ml = x ml

Therefore, 350 ml are water.

350 ml / 400 ml = 0.875 = \frac{350}{400} = \frac{35}{40} = \frac{7}{8}

So the answer is 7 / 8

5 0
3 years ago
If EG and HJ are parallel lines and mEFI = 130°, what is mGFD?
padilas [110]

Answer:

if EG || HJ,

m GFD = 130°

Step-by-step explanation:

Because, m EFI = m GFD

( vertical opposite angles )

so, m GFD = 130°

3 0
2 years ago
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