D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E
therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
Answer:
Step-by-step explanation:
L=3S
In 5 years,
L+5=2(S+5)
L+5=2S+10
L=2S+5
Substituting from above,
3S=2S+5
S=5
So then,
L=3(5)
L=15
To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Answer:
-13
Step-by-step explanation:
(-1/3)*6 = -2
f(-1/3) = -2 -11
f(-1/3) = -13
$249.......................................
