Step-by-step explanation:
find the area as if it was a rectangle so do 14x12 then subtract the area of half a circle with a diamater of 12
Answer: If the level of confidence is increased without changing the sample size then<em> </em><u><em>The margin of error will decrease because the critical value will decrease. The decreased margin of error will cause the confidence interval to be narrower.</em></u>
where;
<em>Margin of error = Critical value × Standard deviation</em>
<em>Here, it can be duly noted that Margin of error has a positive relation with critical value, i.e </em><u><em>The margin of error will decrease because the critical value will decrease.</em></u>
<u><em>whereas;</em></u>
The confidence interval is <em>the value ± the margin of error.</em>
<em>Therefore, </em><u><em>the decreased margin of error will cause the confidence interval to be narrower.</em></u>
Answer:
y = -2x - 2
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Points: (3, 4)
Slope: -2
y = -2x + b
4 = -2 ( 3 ) + b
4 = -6 + b
b = -2
y = -2x - 2
According to Vieta's Formulas, if
are solutions of a given quadratic equation:
Then:
is the completely factored form of
.
If choose
, then:
So, according to Vieta's formula, we can get:
But
:
![d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2](https://tex.z-dn.net/?f=d%5E4-8d%5E2%2B16%3D%28d%5E2-4%29%5E2%3D%5B%28d%2B2%29%28d-2%29%5D%5E2%3D%28d%2B2%29%5E2%28d-2%29%5E2)
These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.
We know that we can solve one variable equation easily. For example...
x+1=2
x=1 obviously
Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.
So what can we do? We have to make a two variable equation into a one variable equation.
There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.
x+y=2
2y-y=1
3)
-3x-5y=-7 -----> -12x-20y=-28
-4x-3y=-2 ------> -12x-9y=-6
-12x-20y=-28
-(-12x-9y=-6)
---------------------
-11y=-22
y=2
-3x-5(2)=-7
-3x=3
x=-1
4) 8x+4y=12 ---> 24x+12y=36
7x+3y=10 ---> 28x+12y=40
28x+12y=40
-(24x+12y=36)
---------------------
4x=4
x=1
8(1)+4y=12
4y=4
y=1
5) 4x+3y=-7
-2x-5y=7 ----> -4x-10y=14
4x+3y=-7
+(-4x-10y=14)
-------------------
-7y=7
y=-1
4x+3(-1)=-7
4x=-4
x=-1
6) 8x-3y=-9 ---> 32x-12y=-36
5x+4y=12 ---> 15x+12y=36
32x-12y=-36
+(15x+12y=36)
--------------------
47x=0
x=0
8(0)-3y=-9
-3y=-9
y=3
7)-3x+5y=-2
2x-2y=1 ---> x-y=1/2 ----> x=y+1/2
-3(y+1/2)+5y=-2
-3y-1.5+5y=-2
2y=-0.5
y=0.25
2x-2(0.25)=1
2x=1.5
x=0.75
