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3 years ago

I need help if anyone can do this.

Mathematics

2 answers:

dolphi86 [110]3 years ago

7 0

The answer should be, D.

Tom [10]3 years ago

3 0

Answer:

The answer would be 12ft. by 10ft.

Step-by-step explanation:

If each inch is equal to 2ft, then you have to multiply both numbers by 2, and change the measurement. 6x2 is 12, and 5x2 is 10.

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An equilateral triangle and an isosceles triangle share a common side. What is the measure of angle ABC? I need help with questi

Ostrovityanka [42]

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8 0

4 years ago

The sum of two numbers is 24. the diffrence is 10. what are the numbers

topjm [15]

Answer:

The two numbers are 17 and 7.

Step-by-step explanation:

x+y=24

x-y=10

------------

2x=34

x=34/2

x=17

17-y=10

y=17-10

y=7

6 0

3 years ago

I need help with number 7 can someone explain how u get the answer?

Svet_ta [14]

Answer:

5 months

Step-by-step explanation:

Set up an inequality, using x to represent months.

(The 35 and 40 represent the cost per month, and you add the 100 and 75 just once because it's a one-time fee and not monthly)

35x + 100 < 40x + 75

Now solve for x.

5x > 25

x > 5

This means that the membership will be less expensive after 5 months.

5 0

4 years ago

A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f

NNADVOKAT [17]

Answer:

$26 - \sqrt{181}$ cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares, in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}$

$x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}$

$x = \frac{624 \pm \sqrt{104256}}{24}$

$x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}$

$x = \frac{624 \pm 8*3*\sqrt{181}}{24}$

$x_1 = \frac{624 + 24*\sqrt{181}}{24}$

$x_1 = 26 + \sqrt{181}$

$x_2 = \frac{624 - 24*\sqrt{181}}{24}$

$x_2 = 26 - \sqrt{181}$

But $x_1 > 33$ , then is not the correct answer.

5 0

3 years ago

Someone help

Bond [772]

Answer:

Step-by-step explanation:

Your numbers are stated in terms of miles. Greenville is a total of 120 miles from Rick. He drives x number of miles and sees that there is still 20 miles to go, so at the end of the driving, he has driven the unknown number of miles, x plus the 20 to get where he's going. That expression is x + 20. We set that equal to the total number of miles he has to drive and we get the expression for the trip to be x + 20 = 120, option C.

3 0

4 years ago