Both of these types of rocks would be susceptible to weathering and erosion.
Thus, the answer would be:
C. Both igneous rocks and metamorphic rocks.
Answer:
( -6, 1 ) is the coordinate of N.
Answer:
x = 4(y + 6)/5
Step-by-step explanation:
2x - y = (3/4)x + 6
2x - (3/4)x = y + 6
(8x - 3x)/4 = y + 6
5x/4 = y + 6
5x = 4(y + 6)
5x = 4y + 24
x = (4y + 24)/5
Therefore, x = 4(y + 6)/5
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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Answer:
x = 3 and x = -2
Step-by-step explanation:
The given equation is :
We need to solve the given equation.
We can solve it using Completing the Square method.
We take two numbers such that their product is -6 and sum is -1.
So,
so, the values of x are 3 and -2.
