22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
The answer would be c because I know
<span>The area of the base is x^2> The height is h. Each side of the box has area xh. There are 4 sides of the box so the total surface area of the box is x^2+4xh and that is equal to 1000. Solve that equation for h:
x^2+4xh = 1000 h = (1000-x^2)/4x so the Volume = x^2[(1000-x^2)/4x]
Simplify and get V = 250x-x^3/4
The volume will be a maximum when its first derivative is 0.
V' = 250-3/4x^2
Set to 0 and solve. x=18.26
Now plug into the volume function to find the maximum volume:
V=250(18.26)-(18.26)^3/4
V= 4564.35 - 1522.10 =3042.25</span>
Option E:
The value of m that makes the inequality true is 5.
Solution:
Given inequality is 3m + 10 < 30.
Let us first simplify the expression.
3m + 10 < 30
Subtract 10 from both side of the equation.
3m < 20 – – – – (1)
<u>To find the value of m that makes the inequality true:</u>
Option A: 20
Substitute m = 20 in (1),
⇒ 3(20) < 20
⇒ 60 < 20
It is not true because 60 is greater than 20.
Option B: 30
Substitute m = 30 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option C: 8
Substitute m = 8 in (1),
⇒ 3(8) < 20
⇒ 24 < 20
It is not true because 24 is greater than 20.
Option D: 10
Substitute m = 10 in (1),
⇒ 3(30) < 20
⇒ 90 < 20
It is not true because 90 is greater than 20.
Option E: 5
Substitute m = 5 in (1),
⇒ 3(5) < 20
⇒ 15 < 20
It is true because 15 is less than 20.
Hence the value of m that makes the inequality true is 5.
Option E is the correct answer.
Answer:
It's a horizontal line passing through 4 on the y-axis.
Simply place a ruler at 4 and draw a straight line from left to right, which passing through the number 4.
