If the base of a triangle is 20mm and the area of the triangle is 40m2. then what will be the height and how can we find it

Mathematics

2 answers:

Nata [24]2 years ago

6 0

Answer: 4 mm

Step-by-step explanation: this is because if you double the area then you will get the Area of 80 and if you divide it by 20 you will get 4 mm

Eddi Din [679]2 years ago

3 0

Use the formula for area of a triangle:

Area = 1/2 x base x height.

Fill in what you know:

40 = 1/2 x 20 x height

Multiply both sides by 2:

80 = 20 x height

Divide both sides by 20

Height = 4 m

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A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located

makkiz [27]

The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is $d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}$

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9):
 $d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63$

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
$d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93$

Distance 3: Los Angeles (–33, –4) to San Francisco (–36, 5)
 $d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49$

D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05

3 0

2 years ago

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zloy xaker [14]

Answer:

Step-by-step explanation:

3 0

2 years ago

HELP ASAP ASAP PLEASE

boyakko [2]

Answer:

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