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kicyunya [14]
2 years ago
7

Given that tan θ ≈ 1.072, where 0 < θ < , 2 π find the values of sin θ and cos θ.

Mathematics
1 answer:
anygoal [31]2 years ago
5 0

Answer:

The answer to your question is

sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682

Step-by-step explanation:

tan Ф = 1.072,  0 < Ф < 2 π,   tan Ф is positive, find the solution in the first and third quadrangle.

- tan Ф = opposite side / adjacent side

- 1.072 / 1 = opposite side / adjacent side

- opposite side = 1.072 and adjacent side = 1

  Calculate hypotenuse

  c² = a² + b²

  c² = 1.072² + 1²

  c² = 2.149

  hypotenuse = c = 1.466

First quadrangle

  sin Ф = 1.072 / 1.466 = 0.731

  cos Ф = 1 / 1.466 = 0.682

Third quadrangle

  sin Ф = -1.072 / 1.466 = -0.731

  cos Ф = -1 / 1.466 = -0.682

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