Answer:
The given equation is
⇒y≥
As domain of the function is 3 x-2≠0
x≠2/3
⇒For different values of x we get different values of y.
When, x>2/3 , we get positive values of y.
So , y≥ 0
and when x< 2/3 , we get values of y which are negative.
i.e y≤0
At x=2/3, function is not defined.So at that point there does not exist any value of y.
Answer:
Step-by-step explanation:
\frac{27}{40} in a decimal is 0.675
.5 is basically 1/2. We know this because .5 written as a fraction is 50/100 which you can simplify to 1/2.
6/10 is greater than 1/2. You can find this out by converting 1/2 to tenths. Multiply the numerator and the denominator by 5 to get 5/10. From there you can easily see that 6/10 > 5/10.
As for the number line simply use 10ths: 1/10, 2/10, 3/10 ... and input 6/10 and 5/10 in the appropriate areas.
First if each stack has 10 cds and there is 5 stacks you do 10 X 5= 50. then you add two more stacks of 10 ( 2 stacks of 10=20) and add 20 to 50 which is 70
That equation is the same as 3m=0, only m=0 works. Do you think they want you to say, all numbers but zero are excluded? Or is the equation different?
