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Anna [14]
3 years ago
13

50 points and brainliest!

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

3a-b/(x-b)=1/(x+1)Doing criss cross multiplication

3a(x+1)-b(x+1)=x-b

3ax+3a-bx-b=x-b

3ax-bx-x=b-3a-b

x(3a-b-1)=-3a

x=3a/(3a-b-1)

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A car is traveling at when the driver sees an accident m ahead and slams on the brakes. What constant deceleration is required t
EleoNora [17]

Answer:

Deceleration = \frac{v^2}{2a} units/sec^2

Step-by-step explanation:

Given that a car is traveling at when the driver sees an accident m ahead and slams on the brakes.

i.e. if he is coming with speed v units/sec say, he has to make his velocity 0.

Distance travelled = m units

Initial velocity = v

Final velocity =0

Use the third formula as

v^2=u^2+2as\\0=v^2+2am\\a =\frac{-v^2}{2a}

So he has to apply an acceleration of \frac{-v^2}{2a} units/sec^2 to stop the car in time to avoid a pile up.

Deceleration = \frac{v^2}{2a} units/sec^2

8 0
3 years ago
In an election, the population consists of the people who voted. Although there is overall data on how the population voted, the
andrew-mc [135]

Answer:

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

Step-by-step explanation:

braniest

4 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
E^(i.π)+2^(-2+3-1)+21899921030
Anna007 [38]

Answer:

21899921030

Step-by-step explanation:

e^(i.π) = -1

2^(-2+3-1) = 2^0 = 1

Therefor

-1 + 1 + 21899921030 = 21899921030

5 0
2 years ago
What is special about a 30 60 90 triangle?
Nata [24]
A 30-60-90 triangle is special because of the relationship of its sides. Also <span>It turns out that in a 30-60-90 triangle, you can find the measure of any of the three sides, simply by knowing the measure of at least one side in the triangle.

Hope this helps. :)</span>
7 0
3 years ago
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