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Anna [14]
3 years ago
13

50 points and brainliest!

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

3a-b/(x-b)=1/(x+1)Doing criss cross multiplication

3a(x+1)-b(x+1)=x-b

3ax+3a-bx-b=x-b

3ax-bx-x=b-3a-b

x(3a-b-1)=-3a

x=3a/(3a-b-1)

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Peter is writing a number in scientific notation.The number is grater that ten million and less that one hundred million.Which e
OLga [1]

Answer:

M  =  a \times 10^7  where 1 < a ≤ 9

The EXPONENT USED BY PETER is 7 in all the possible cases.

Step-by-step explanation:

Let us assume the needed number is M.

Also, given:

The needed number is GREATER than 10 Million.

⇒ M  > 10 Million

⇒ M > 10,000,000

⇒ M > 1 \times 10^7  ...... (1)

The needed number is SMALLER than 100 Million.

⇒ M  <  100 Million

⇒ M < 100,000,000

⇒ M  <  1 \times 10^8  ...... (2)

Comparing (1) and (2) we can see that M can have more than 7 zeroes after 1 but LESS than 8 zeroes after 1.

So, the possible values of M can be:

M  =  a \times 10^7  where 1 < a ≤ 9

So, the EXPONENT USED BY PETER is 7 in all the possible cases.

5 0
4 years ago
Simplify the following 3√28-5√63+4√112
alexandr402 [8]

7√7

using the ' rule of radicals '

• √a × √b ⇔ √ab

simplifying the radicals

√28 = √(4 × 7 ) = √4 × √7 = 2√7

√63 = √(9 × 7) =√9 × √7 = 3√7

√112 = √(16 × 7 ) = √16 × √7 = 4√7

substituting into the expression

3(2√7) - 5(3√7) + 4(4√7) = 6√7 - 15√7 + 16√7 = 7√7


7 0
3 years ago
Read 2 more answers
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Three hundred four million, Eight hundred thousand Four hundred
and standard form is the way you wrote it, 304,800,400
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3 years ago
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weqwewe [10]
Sqrt 13 and 1.1919919991... are irrational, meaning that they can't be described in a fraction of one integer over another, like 1/3, 45/44 or 57/107, these numbers are rational. Most irrationals are known constants like e or π, endless non-repeating decimals, or roots of non-perfect numbers like 13, 7, 5 or 2.
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Ann opened a new savings account with an initial deposit of $250. Which combination will result in a zero in balance in Ann's ac
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C.  (10x3)10 - (27.5x2)10 = 0
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