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Korolek [52]
3 years ago
5

the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

n the parabolas equation
Mathematics
1 answer:
otez555 [7]3 years ago
6 0
Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a
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<u>Given</u>:

Line m is parallel to line n.

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<u>Value of x:</u>

From the figure, it is obvious that ∠1 and ∠2 are linear pairs.

Thus, we have;

\angle 1+\angle 2=180^{\circ}

Substituting the measures of ∠1 and ∠2, we get;

4x+15+9x+35=180

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Thus, the value of x is 10.

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The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1

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Rus_ich [418]

Answer:

Options (1), (3), and (4)

Step-by-step explanation:

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Therefore, slope of a line passing through (0, 5) and (2, 8) will be,

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Therefore, equation of a line passing through (0, 5) and slope = 1.5,

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Since, all the points which lie on this line will satisfy this equation.

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11 = 1.5(4) + 5

11 = 11

Point (4, 11) lies on this line.

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10 = 1.5(5) + 5

10 = 7.5 + 5

10 = 12.5

But 10 ≠ 12.5

Therefore, (5, 10) doesn't line on the line.

Point (6, 14)

14 = 1.5(6) + 5

14 = 14

True.

Therefore, (6, 14) lies on the line.

Point (30, 50)

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Therefore, (30, 50) lies on the line.

Point (40, 60)

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60 = 65

But 60 ≠ 65

Therefore, (40, 60) doesn't lie on the line.

Options (1), (3) and (4) and the correct options.

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