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Korolek [52]
3 years ago
5

the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

n the parabolas equation
Mathematics
1 answer:
otez555 [7]3 years ago
6 0
Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a
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