What is the total number of electrons needed to completely fill all of the orbitals in an atoms second principal energy level
Answer:
2.30 × 10⁻⁶ M
Explanation:
Step 1: Given data
Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M
Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³
Step 2: Write the reaction for the solution of Mg(OH)₂
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂
We will use the following expression.
Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²
[OH⁻] = 2.30 × 10⁻⁶ M
Na3PO4 + 3 KOH = 3 NaOH + K3PO4
Answer: pH = 7.36. The pKa of H2PO4− is 7.21.
Explanation:
According to the <span>Le
Chatelier's Principle, if a condition of system is changed, then the system try
to become equilibrium again by correcting that change.
N2(g) + 3H2(g) ⇄<span> 2NH3(g)
If H2(g) is added, then the concentration of H2(g) is high in the system. So
the system tries to reduce it and become to equilibrium
state. Hence to reduce that H2(g) the forward reaction is promoted. Then
Concentration of product, NH3 gas
is increased.</span></span>