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Marrrta [24]
3 years ago
6

predict what will happen to the ammonia equilibrium system if hydrogen gas (H2) is added in the following reaction. N2(g) + 3H2(

g) ⇄ 2NH3(g) (2 points)
Chemistry
1 answer:
labwork [276]3 years ago
4 0

According to the <span>Le Chatelier's Principle, if a condition of system is changed, then the system try to become equilibrium again by correcting that change. 

N2(g) + 3H2(g) ⇄<span> 2NH3(g)

If H2(g) is added, then the concentration of H2(g) is high in the system. So the system tries to reduce it and become to equilibrium state. Hence to reduce that H2(g) the forward reaction is promoted. Then Concentration of product, NH3 gas is increased.</span></span>

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A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p
Salsk061 [2.6K]
Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====>  H2O + 2CO2
CH4 +  2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of  CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water. 

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2  we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y =  972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so. 
x = 8.03 moles
y = 1.38 moles 

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
6 0
3 years ago
Why was Newland’s periodic table rejected?
Rina8888 [55]
He put iron with sulfur and oxygen and it had a few more errors and iron is a metal the other two are nonmetals

5 0
3 years ago
Consider 10.0 g of helium gas (He) in a rigid steel container. If you add 10.0 g of neon gas (Ne) to this container, which of th
Norma-Jean [14]

Answer: (e) The pressure in the container increases but does not double.

Explanation:

To solve this, we need to first remember our gas law, Boyle's law states that the pressure and volume of a gas have an inverse relationship. That is, If volume increases, then pressure decreases and vice versa, when temperature is held constant. Therefore, increasing the volume in this case does not double the pressure owning to out gas law, but an increase in pressure would be noticed if temperature is constant

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Lawrencium-262 has a half-life of 4 hr. How much of a 40 mg sample remains after 12 hours?
CaHeK987 [17]

Answer:

5 mg

Explanation:

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This means that the sample will decay to 1/8 of its original amount.

So, the answer is 40(1/8) = 5 mg.

3 0
2 years ago
Are these answers correct? I’m a little unsure
Naily [24]

Answer:

yes I think that they are correct

8 0
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