Answer:
0.5
Step-by-step explanation:
This is an example of mutually exclusive event in which two or more events cannot occur at the same time or in a single performance.
Therefore, the probability the number of cars entering the roadway is between 4 and 6 cars per minute (inclusive) implies that it is either 4, 5 or 6 cars enter in a minute. Since we have an average of 6 cars per minute, the probability of each of the event occurring is 1/6. This can therefore be calculated as follows:
P(4 or 5 or 6) = (1/6) + (1/6) + (1/6)
= 3/6
= 1/2
= 0.5
Therefore, the probability the number of cars entering the roadway is between 4 and 6 cars per minute (inclusive) is 0.5.
Product means the result you get after multiplying. So you have to multiply the two numbers. 379*8 = 3032
If you take 4/6, you divide so it will be 0.6667... and then if you take 5/7 you divide again, and then it will be 0.7143...
2x³+18x²<span>-18x-162 =
2(</span>x³+9x²-9x-81)=
2(x²(x+9)-9(x+9))=
2(x²-9)(x+9)=
2(x+3)(x-3)(x+9)
Answer: k=3
Answer:
A. -4
B. -3.5
C. 6.5
D. -2
Step-by-step explanation:
The “less” indicates it is negative.
The “more” indicates it is positive.
