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Dennis_Churaev [7]
3 years ago
12

A thermometer is used to measure which of the following?

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

c. i hope im not wrong hmmm

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You are performing a simple distillation of roughly 50:50 liquid solution containing two components, hexane and nonane You place
kicyunya [14]

Answer:

0.38  

Explanation:

As you go from 0 % hexane (χ = 0) to 100 % hexane (χ = 1), the refractive index decreases from 1.407 to 1.375, a decrease of 0.032.

From 1.407 to 1.3948, the decrease is 0.0122 .

That is 0.0122/0.032 = 0.38 of the distance from χ = 0 to χ = 1.

The mole fraction of hexane is 0.38.

The diagram below is a plot of refractive index vs. the mole fraction of hexane. It shows that the refractive index drops to 1.3948 when χ = 0.38.

5 0
3 years ago
A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m
aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( q_{\ lost} )= heat absorbed by the less hotter  sample( q_{\ gain} )

The relationship between heat (q), mass (m) and temperature (t) is q = mc\Delta t

where c is specific heat capacity, \Delta t temperature change.

\Delta t = t_{\ final} - t_{\ initial}

equating both heat emitted and absorb

-q_{\ lost} = q_{\ gain}

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * (t_{final} - 330) = 30 *  (t_{final} - 280)

-50t_{final} + 16500 = 30t_{final} - 8400

80t_{final} = 16500+8400

80t_{final} = 24900

t_{final} = 24900/80 = 311.25k

8 0
3 years ago
Identify the reasons that cities boomed during the Middle Ages.
atroni [7]

Answer:

Explanation:

The reasons that cities boomed during the Middle Ages are more employment opportunities, increased trade, and growing interest in culture and art.

7 0
3 years ago
Read 2 more answers
Identify the balanced chemical equation that represents a combustion reaction. 2C 4H 10 + 13O 2 ⟶ 10H 2O + 8CO 2 C 4H 10 + 5O 2
kati45 [8]

Answer:

  2C₄H₁₀ + 13O₂ ⟶ 10H₂O + 8CO₂

Explanation:

  2C₄H₁₀ + 13O₂ ⟶ 10H₂O + 8CO₂  . . . . .  balanced combustion reaction

  C₄H₁₀ + 5O₂ ⟶ 5H₂O + 4CO₂  . . . . not balanced

The two reactions involving Ca are not combustion reactions.

7 0
3 years ago
A variety of factors influence enzyme activity. Substances that bind to the enzyme and interfere with substrate binding or catal
Fofino [41]
<h3>Answer:</h3>

1. Irreversible Inhibition-Inhibitor may permanently modify an enzyme

2. Irreversible inhibition- Tamiflu, a transition state analog, reversibly binds to neuraminindase

3. Competitive Inhibition-Inhibitor binds reversibly to an enzyme's active

4.Irreversible inhibition-Inhibitor binds to an enzyme at a site other than active site

5. Mixed inhibition-The Al3+ ion binds to acetylcholinesterase or to the acetylcholinesterase- substrate complex

6. Irreversible inhibition-DIPF permanently modifies the hydroxyl group of a Serine residue at the active site

<h3>Explanation:</h3>
  • An enzyme is a biological catalyst that catalysis chemical reactions.
  • Enzyme activity is influenced by several factors which include enzyme inhibitors, temperature, and pH among others.
  • Enzyme inhibitors are molecules that bind to the enzyme thus interfering with enzyme activity and preventing the binding of substrate to the enzyme.
  • Inhibitors may either irreversibly or reversibly bind the enzymes.
  • Competitive inhibitors compete with substrates for the active sites while non-competitive inhibitors bind irreversibly to other sites on the enzyme other than the active site.
  • Tamiflu is an example of a competitive inhibitor.
  • DIPF is an example of a non-competitive inhibitor as it binds the enzyme permanently.

3 0
4 years ago
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