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3 years ago

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Identify the balanced chemical equation that represents a combustion reaction. 2C 4H 10 + 13O 2 ⟶ 10H 2O + 8CO 2 C 4H 10 + 5O 2

⟶ 5H 2O + 4CO 2 CaCO 2 ⟶ Ca + CO 2 2CaCO 2 ⟶ 2Ca + CO 2

1 answer:

kati45 [8]3 years ago

7 0

Answer:

2C₄H₁₀ + 13O₂ ⟶ 10H₂O + 8CO₂

Explanation:

2C₄H₁₀ + 13O₂ ⟶ 10H₂O + 8CO₂ . . . . . balanced combustion reaction

C₄H₁₀ + 5O₂ ⟶ 5H₂O + 4CO₂ . . . . not balanced

The two reactions involving Ca are not combustion reactions.

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How many formula units make up 24.2 g of magnesium chloride (MgCl2)?<br><br> Help!!

NNADVOKAT [17]

Answer:

Approximately $1.53 \times 10^{23}$ formula units ( $0.254\; \rm mol$ ).

Explanation:

Refer to a modern periodic table for the relative atomic mass of magnesium ( $\rm Mg$ ) and chlorine ( $\rm Cl$ ):

$\rm Mg$ : $24.305$ .
$\rm Cl$ : $35.45$ .

In other words, the mass of $1\; \rm mol$ of $\rm Mg$ atoms would be (approximately) $24.305\; \rm g$ .

Likewise, the mass of $1\; \rm mol$ of $\rm Cl$ atoms would be approximately $35.45\; \rm g$ .

One formula unit of the ionic compound $\rm MgCl_{2}$ includes exactly as many atoms as there are in the given formula. The formula mass of a compound is the mass of $1\; \rm mol$ of the formula units of this compound.

The formula $\rm MgCl_{2}$ includes one $\rm Mg$ atom and two $\rm Cl$ atoms.

Hence, every formula unit of $\rm MgCl_{2} \!$ would include the same number of atoms: one $\rm Mg\!$ atom and two $\rm Cl\!$ atoms. There would be $1\; \rm mol$ of $\rm Mg$ atoms and $2\; \rm mol$ of $\rm Cl$ atoms in $1\; \rm mol\!$ of $\rm MgCl_{2}$ formula units.

Thus, the mass of $1\; \rm mol\!$ of $\rm MgCl_{2}$ formula units would be equal to the mass of $1\; \rm mol$ of $\rm Mg$ atoms plus the mass of $2\; \rm mol$ of $\rm Cl$ atoms. (The mass of $1\; \rm mol\!\!$ of each atom could be found from the relative atomic mass of each element.)

$\begin{aligned}& M({\rm MgCl_{2}}) \\ =\; & 24.305\; {\rm g \cdot mol^{-1}} + 2\times {\rm 35.45 \; \rm g \cdot mol^{-1}} \\ =\; & 95.205\; \rm g \cdot mol^{-1}\end{aligned}$ .

In other words, the formula mass of $\rm MgCl_{2}$ is $95.205\; \rm g \cdot mol^{-1}$ .

Therefore, the number of formula units in $m = 24.2\; \rm g$ of $\rm MgCl_{2}$ would be:

$\begin{aligned}n &= \frac{m({\rm MgCl_{2}})}{M({\rm MgCl_{2}})} \\ &= \frac{24.2\; \rm g}{95.205\; \rm g\cdot mol^{-1}} \\ & \approx 0.254\; \rm mol\end{aligned}$ .

Multiple $n$ by Avogadro's Number $N_{A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}$ to estimate the number of formula units in $0.254\; \rm mol$ :

$\begin{aligned}N &= n \cdot N_{A} \\ &\approx 0.254\; \rm mol \times 6.022 \times 10^{23}\; \rm mol^{-1} \\ &\approx 1.53\times 10^{23}\end{aligned}$ .

6 0

3 years ago

Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fue

Nesterboy [21]

Answer:

$1.7\cdot 10^{15} g$

Explanation:

Glucose reacts with oxygen do produce carbon dioxide and water:

$C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)$

Given a daily mass of glucose:

$m_1 = 5.0\cdot 10^2 g$

Find moles of glucose:

$n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol$

From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:

$n_2 = 2.775 mol\cdot 6=16.65 mol$

Convert this into mass using the molar mass of carbon dioxide:

$m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g$

This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:

$732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g$

5 0

3 years ago

What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250

kifflom [539]

Answer:

Molarity =5.32 M

Explanation:

Given data:

Mass of glucose = 239 g

Volume = 250 mL (250 /1000 = 0.25 L)

Molarity = ?

Solution;

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 239 g / 180.2 g/mol

Number of moles = 1.33 mol

Molarity:

Molarity = number of moles / volume in litter

Molarity = 1.33 mol / 0.25 L

Molarity =5.32 M

6 0

3 years ago

Which ones are all renewable resources?

9966 [12]

D, they can be renewed quickly rather than non renewables in which nonrenewable take millions of years. Biomass is all around us, so is water (hydro) and the sun is around us too.

3 0

3 years ago

Read 2 more answers

A sample of gold has a mass of 15.7 g and displaces 0.81 cm3 of eater in a graduated cylinder. What is the density of gold?

Ostrovityanka [42]

Answer: 19.4 g/cm3

Explanation: density is the relationship between mass over volume.

So density of gold is 15.7g/0.81cm3 = 19.4 g/cm3

3 0

3 years ago