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valentinak56 [21]
3 years ago
12

Wanna see me run to that hill? Wanna see me do it again?

Mathematics
2 answers:
kondaur [170]3 years ago
7 0

Answer: uhh no but thanks for the points

Step-by-step explanation:

wolverine [178]3 years ago
7 0
Sure lemme see you do it again
You might be interested in
If the polynomials p(x)=2x³ +bx² +3x-5 and q(x)= x³+x² -4x-b leave the same remainder, when divided by x-2, prove that b = -13/5
Tju [1.3M]

Step-by-step explanation:

Lets first find the remainder when p(x) is divided by x-2

p(2)=2(2)³+b(2)²+3(2)-5

p(2)=16+4b+6-5

p(2)=4b+17

Now let's find the remainder when q(x) is divided by x-2

q(2)=(2)³+(2)²-4(2)-b

q(2)=8+4-8-b

q(2)=4-b

Now let's equate both of them

4b+17=4-b

4b+b=4-17

5b=-13

b=-13/5 as required

5 0
2 years ago
The Super Shop is having a grand opening sale. Today's special includes 4
KATRIN_1 [288]

Answer:

11

Step-by-step explanation:

4d=44

4d/4=44/4

d=11

the cost is 11$ per dress

8 0
3 years ago
1. A rabbit can hop 6 feet in 2 seconds and 12 feet in 4 seconds. If the number of feet varies directly with the time the rabbit
kykrilka [37]

Answer: The rabbit is hopping at 3 feet/ sec in speed

Step-by-step explanation:

Step 1

Let the The number of feet of the rabbit be expressed as N

AND  time rabbit spends hopping can be expressed  as  t

From the question,  The number of feet varies directly with the time rabbit spends hopping can be expressed  as

N α t

Let us introduce a constant of proportionality ,S which represents  speed in this case, we now have that

N = St

STEP 2 -- SOLVING

If the rabbit hop 6 feet in 2 seconds, Then speed =

N = St

6=  S X2

S = 6/ 2

S = 3

also

If the rabbit hop 12 feet in 4 seconds, Then speed =

N = St

12=  S X 4

S = 12/ 4

S = 3

Also recall

that Speed = Distance / time

Pluging the values in the first case,

speed = 6 feet/ 2 secconds = 3 feet/ seconds

in the second case

Speed= 12 feet/ 4 second s= 3 feet/ secs.

5 0
2 years ago
(b) For a function h(theta)=sin3 theta (Theta is in Radian). <br> Find h(pi/3)<br> Find h(pi/2)
vaieri [72.5K]

Part (i)

Plug in theta = pi/3 to get

h(theta) = sin(3theta)

h(pi/3) = sin(3*pi/3)

h(pi/3) = sin(pi)

h(pi/3) = 0 ... use a calculator or the unit circle

<h3>Answer: 0</h3>

=================================================

Part (ii)

Plug in h = pi/2

h(theta) = sin(3theta)

h(pi/2) = sin(3pi/2)

h(pi/2) = -1

<h3>Answer:  -1</h3>
5 0
3 years ago
Simplify: sec(θ) sin(θ) cot(θ)
krek1111 [17]

We have to simplify

sec(θ) sin(θ) cot(θ)

Now first of all let's simplify these separately , using reciprocal identities.

Sec(θ) = 1/cos(θ)

Sin(θ) is already simplified

Cot(θ)= cos(θ) / sin(θ) ,

Let's plug these values in the expression

sec(θ) sin(θ) cot(θ)

= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )

= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

sin cancels out with sin and cos cancels out with cos

So , answer comes out to be

=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

= 1

4 0
3 years ago
Read 2 more answers
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