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3 years ago

Please help with this math problem

Mathematics

1 answer:

nekit [7.7K]3 years ago

7 0

The answer to your problem is -8/-3

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Please find the missing ? Explanation need it

uranmaximum [27]

Answer:

the answer is 3.162

Step-by-step explanation:

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3 years ago

Could I have help if any of these problems?

valentinak56 [21]

Question 27 The answer is x = 1 4/11

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4 years ago

The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side

kkurt [141]

The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.

SOLUTION:

Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.

Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.

That is, length of largest side = 3n inches

The other two sides are equally long and are 4 inches longer than the shortest side.

Then, length of remaining two sides = 4 + n inches

We have to find the length of all four sides.

Now, we know that, perimeter = 50 inches

$\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}$

So, length of sides will be,

$7 \text { inches; } 3\times7=21 \text { inches; } 7+4=11 \text { inches; } 7+4=11 \text { inches. }$

6 0

4 years ago

If you toss a pair of dice 1,000 times, how many times would you expect to get a sum of 12 as the result?

SIZIF [17.4K]

If you toss a pair of dice 1,000 times, how many times would you expect to get a sum of 12 as the result. When you toss a die there is 1/6 probility that you will get 6 so if you toss another die the probability is the same. The get a sum of 12 the probability is 1/36.

So if you toss 1000 times,

You will get about 1000 (1/36) = 27 times

6 0

3 years ago

Theoretically, if a month is chosen 300 times,

horsena [70]

Answer:

75 times.

Step-by-step explanation:

Well there are 12 months and 3 of them start with the letter J, so theoretically, 25% of the months chosen will start with the letter J because $\frac{3}{12}=\frac{1}{4}$ , which is 25%. 25% of 300 (or $\frac{300}{4}$ , for those who like fractions) is 75, so theoretically, we can expect a month that starts with the letter J 75 times.

Hope this helps!

P.S: Please mark me as brainliest!

6 0

3 years ago