Let
x----------> number of weeks
y----------> saved money
we now that
<span>Michael begins with $20 and saves $5 per week
so
y=20+5x------> equation 1
and
</span><span>Lindsey begins with no money, but saves $10 per week
</span><span>y=10x-------> equation 2
</span><span>the number of weeks it will take for Lindsey and Michael to save the same amount of money is when equation 1 is equals to equation 2
</span>
therefore
20+5x=10x------> 10x-5x=20------> 5x=20-----> x=20/5-----> x=4 weeks
the answer is
4 weeks
Answer:
12.1x+t
Step-by-step explanation:
since we do not get a specific amount we must add 4.8 and 7.3 and substitute the amount the driver earns per mile with x and use t as a variable if they charge something like $5 just to get in before driving
Answer:
(cx)2-(dy) 2
Step-by-step explanation:
Formula a2-b2= (a+b) (a-b)
By given formula
(cx)2 - (dy) 2 = (cx+dy) (cx-dy)
Well its
900+0+0
basically
like if it was
9,234
then it would be
9000+200+30+4
Answer:
8.9%
Step-by-step explanation:
Here, we are to calculate the probability of Howard choosing a chocolate candy followed by a gummy candy.
The probability of selecting a chocolate candy = number if chocolate candy/ total number of candy
Total number of candy = 5 + 4 + 6 = 15
Number of chocolate candy = 5
The probability of selecting a chocolate candy = 5/15 = 1/3
The probability of selecting a gummy candy = number of gummy candies/total number of candies
Number of gummy candy = 4
The probability of selecting a gummy candy = 4/15
The probability of selecting a chocolate candy before a gummy candy = 1/3 * 4/15 = 4/45 = 0.088888888889
Which is same as 8.89 percent which is 8.9% to the nearest tenth of a percent
