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3 years ago

please answer quickly First to answer quickly will be marked the brainiest and get 50 points. the question is in the image below

Mathematics

1 answer:

Bas_tet [7]3 years ago

4 0

Whole number is 3
Integer but not whole is 1/2
Rational Number is 49/7
Irrational Number is 89/10

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The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any meth

Lubov Fominskaja [6]

Answer:

$\frac{128\pi}{3}$ cubic units

Step-by-step explanation:

We are given that a region bounded by a curves $x=(y-7)^2$

x=4 and about y=5

We have to find the value of volume of the resulting solid

To find the volume of resulting solid we are using cylinder method

Substitute the values of x then we get

$(y-7)^2=4$

$y-7=\pm2$

y-7=2 and y-7=-2

y=7+2=9 and y=-2+7=5

Radius of cylinder =r=y-5

and height =h= $4-(y-7)^2=4-y^2-49+14 y=-y^2+14 y -45$

Using cylinder method and integrate along y -axis from y=5 to y=9

Volume = $\int_{a}^{b}2\pi r h dy=\int_{5}^{9}2\pi(y-5)(-y^2+14 y -45) dy$

volume= $2\pi\int_{5}^{9}(-y^3+19y^2-115y+225)dy$

Volume = $2\pi[-\frac{y^4}{4}+19\frac{y^3}{3}-115\frac{y^2}{2}+225y]^9_5$

Volume = $2\pi[-\frac{6561}{4}+\frac{625}{4}+19(\frac{729-125}{3})-115(\frac{81-25}{2})+225(9-5)]$

Volume= $2\pi(-1484+\frac{11476}{3}-3220+900)$

Volume = $2\pi(\frac{11476}{3}-3804)$

Volume = $2\pi(\frac{11476-11412}{3})=\frac{128\pi}{3}$

Hence, volume of resulting solid = $\frac{128\pi}{3}$ cubic units

3 0

3 years ago

Which two integers is √65 between?

goblinko [34]

The answer to this math problem is the multiple is 1 5 13

7 0

3 years ago

Read 2 more answers

I need help solving this problem with proofs if at all possible

k0ka [10]

I don't really like these algebra problems which pretend to be geometry.

The bisector makes two equal angles, so

x/2 + 17 = x - 33

50 = (1/2) x

x = 100

That means ABC = 100/2 + 17 = 67 degrees

CBD = 100 - 33 = 67 degrees, equal so that checks

We're asked for ABC which is 67 + 67 = 134 degrees

Answer: 134°

4 0

3 years ago

Read 2 more answers

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 gree

Leni [432]

Answer: The correct answer is option B: There are between 15 and 20 green pieces in all 5 packages

Step-by-step explanation: The most important factor has been given which is, "Which statement about the candy pieces in the remaining packages is best supported by this information."

The information given is such that, the first package she opened had 4 green pieces and on this basis we can safely assume that all other packages have 4 green pieces as well. The second package had 3 green pieces and this based on this too we can safely assume that all other packages had 3 green pieces. Hence, all 5 packages can either have a total of 4 x 5 green candies which equals a total of 20 green pieces or, all 5 packages can have a total of 3 x 5 green candies which equals a total of 15 green pieces.

So according to Suzi's experiment, there are between 15 and 20 green pieces in all 5 packages.

7 0

3 years ago

Answer to this math problem

Cerrena [4.2K]

Subsitute 1/3 for t

$18(\frac{1}{3})^2=18(\frac{1}{9})=\frac{18}{9}=2$

4 0

3 years ago