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rjkz [21]
4 years ago
15

What occurs when electric chargers build up on objects

Mathematics
1 answer:
Nimfa-mama [501]4 years ago
5 0

<u>Answer:</u>

when electric chargers build up on objects is called Static Electricity

<u>Explanation:</u>

When electric charges are built up on objects which can happen due to rubbing or pulling apart of some materials, we get positive charges (+) get collected on surface of one material and negative charges (-) on another. These objects stay charged for some time till they aren't transferred elsewhere through interaction.

This electrically charged surfaces creates a shock type effect when touched. This charging of surfaces of objects due to accumulation of electrons or protons is known as static electricity or static discharge.

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51-11=40 minutes

48-29=19

40+19= 59 minutes

I hope that helped. :)

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3 years ago
Cuantas caras tiene un cubo
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<span>Un cubo tiene seis caras.

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3 years ago
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Find the mean, median and mode(s) of the data. Choose the measure that best represents the data. Explain your reasoning.
r-ruslan [8.4K]
1. 7, 12, 13, 40, 88, 90, 95

Mean- 268.57 or 268.6
Median- 40
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6 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

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3 years ago
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Answer:

This can be expanded to x⁴ - 6x²

Step-by-step explanation:

x^2(x^2 - 6)\\= x^4 - 6x^2

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3 years ago
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