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allsm [11]
3 years ago
9

If 2c - 5 = 3d + 4, what does c equal, in terms of d?

Mathematics
2 answers:
Lina20 [59]3 years ago
8 0

Answer:

d. \:  \frac{3d + 9}{2}

Step-by-step explanation:

Follow the steps below.

2c - 5 = 3d + 4 \\ 2c = 3d + 9 \\ c =  \frac{3}{2} d +  \frac{9}{2}  \: or \: c =  \frac{3d + 9}{2}

So D is correct.

saw5 [17]3 years ago
5 0

Answer:

D. \frac{3d+9}{2}

Step-by-step explanation:

2c - 5 = 3d + 4

Isolate 2c.

2c = 3d + 4 + 5

Simplify.

2c = 3d + 9

(2c ÷ 2 = c) Find c.

c = \frac{3d+9}{2}

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Answer:

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Step-by-step explanation:

From the question we are told that

    The probability of the device failing during the warranty period is p =  0.005

    The  sample size is  n = 3000

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Generally this is distribution is binomial given the fact that there is only two out comes hence

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Now the mean is mathematically evaluated as

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The standard deviation is mathematically represented as

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=>  \sigma  =  \sqrt{3000 *  0.005 * (1 - 0.005 )}

=>   \sigma  =  3.86

Now given that n is very large, then it mean that we can successfully apply normal approximation on this  binomial distribution

So

    P(X \ge  15) =  P( \frac{X - \mu}{\sigma }  \ge \frac{x - \mu}{\sigma } )

Now  applying  Continuity Correction we have

   P(X \ge  (15-0.5)) =  P( \frac{X - \mu}{\sigma }  > \frac{(15 -0.5) - 15}{3.86 } )

Generally  \frac{X - \mu}{\sigma }   =  Z (The \ standardized \ value  \ of  \ X)

    P(X \ge  (15-0.5)) =  P(Z >-0.130 )

From the z-table  

       P(Z >-0.130 )  =0.5

Thus  

    P(X \ge  15) =  0.5

 

   

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