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laiz [17]
3 years ago
10

7. Which expression is equivalent to the expression (5.5 X 107)(3.2 x 10') 2 X 105

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

soln:

(5.5 × 107)

(3.2 × 10')

+ 2 × 105

_______________

8.8. ×.1011

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Which of the following points lie in the solution set to the following system of inequalities? (1 point)
swat32

Answer:

the answer is

The point (1, −5) lie in the solution set

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Solve ~<br><br><img src="https://tex.z-dn.net/?f=2x%20-%2056%20%3D%2014" id="TexFormula1" title="2x - 56 = 14" alt="2x - 56 = 14
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Answer:

x=35

Step-by-step explanation:

Add 56 to both sides of the equation

2x-56+56=14+56

Simplify

2x=70

Divide both sides of the equation by the same term

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you can write it as

-6(x+1)

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I DON’T UNDERSTAND! PLEASE HELP!
Brums [2.3K]

Answer:

The height of the water is 60.5\ ft

Step-by-step explanation:

step 1

Find the volume of the tank

The volume of the inverted right circular cone is equal to

V=\frac{1}{3}\pi R^{2} H

we have

R=16\ ft

H=96\ ft

substitute

V=\frac{1}{3}\pi (16)^{2} (96)

V=8,192\pi\ ft^{3}

step 2

Find the 25% of the tank’s capacity  

V=(0.25)*8,192\pi=2,048\pi\ ft^{3}

step 3

Find the height, of the water in the tank  

Let

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we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

\frac{R}{H}=\frac{r}{h}

substitute

\frac{16}{96}=\frac{r}{h}\\ \\r= \frac{h}{6}

where

r is the radius of the smaller cone of the figure

h is the height of the smaller cone of the figure

R is the radius of the circular base of tank

H is the height of the tank

we  have

V=2,048\pi\ ft^{3} -----> volume of the smaller cone

substitute

2,048\pi=\frac{1}{3}\pi (\frac{h}{6})^{2}h

Simplify

221,184=h^{3}

h=60.5\ ft

6 0
3 years ago
If tan x=2021<br> x=20/21 <br> and <br> π&lt; x &lt; 3π/2<br> what is cos⁡(x+π/2)?
Flura [38]

Answer:

42Sin

Step-by-step explanation:

Speed it up

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