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natita [175]
3 years ago
9

Hat term can you add to StartFraction 5 over 6 EndFraction x minus 4 to make it equivalent to One-half x minus 4?

Mathematics
1 answer:
kolezko [41]3 years ago
8 0

Answer:

\dfrac{-x}{3}should be added to the given equation.

Step-by-step explanation:

Let a is added to the given equation.

According to the given condition,

\dfrac{5x}{6}-4+a=\dfrac{x}{2}-4\\\\a=\dfrac{x}{2}-4+4-\dfrac{5x}{6}\\\\a=\dfrac{x}{2}-\dfrac{5x}{6}\\\\a=\dfrac{3x-5x}{6}\\\\a=\dfrac{-2x}{6}\\\\a=\dfrac{-x}{3}

So, \dfrac{-x}{3}should be added to the given equation.

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Three friends all live on the same street that runs west to east. Ben lives 8 blocks from ann. Carol lives 2 blocks from ben. If
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Answer:

i. 10 units (Carol's house is 10 units on the right from Ann's house)

ii. -10 units (Carol's house is 10 units on the left to Ann's house)

Step-by-step explanation:

A number line is a system that can be used to express the location of directed number on a straight line. It has an origin which is taken to be zero (0).

In the given question, Ann's house is located at 0 of the number line. Let 1 block be represented by 1 unit on the number line.

Thus, Ben lives 8 blocks from Ann implies that Ben's house is at 8 units from Ann's house.

Given that Carol's house is 2 blocks from Ben implies that Carol's house is 2 units from Ben.

So that,

The possible locations of Carol's house depends on its position with respect to Ann's house.

i. Carol's house = 8 + 2

                          = 10 units

This implies that Carol's house is 10 units on the right from Ann's house.

ii. Carol's house = - 8 - 2

                           = -10 units

This implies that Carol's house is 10 units on the left to Ann's house.

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