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Yuki888 [10]
3 years ago
7

Write an expression that can be used to check the quotient of 646 ÷ 3

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0
The expression that can be used to check this quotient which is 646/3 is
 x * 3 = 646.
Ipatiy [6.2K]3 years ago
5 0
646/3=x
To check it: x*3 should =646
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13.62<br><br> Round to the<br> nearest whole<br> number.
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Answer:

14

Step-by-step explanation:

when rounding you round up when the number is 5+ but if it's anything below 5 you go down instead, making this answer being 14

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Triangle DEF is congruent to D'EF' by the SSS theorem. Which single rigid transformation is required to map DEF onto D'EF'?
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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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2 years ago
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Answer: i guess the problem is with P(x) => "x = x^{2}", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and 0^{2} = 0. So p(0) is true.

b) x = 1 and 1^{2} = 1, so P(1) is true.

c) x = 2, and 2^{2} = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and 1^{2} = 1, and 1 ≠ -1, so P(-1) is false.

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Brad swims 4 laps every 6min how long does it take him to swim 14 laps?
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I don’t know the answer
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