If I have eight numbers and i am tasked to decide which of the set of given numbers is the smallest comparing 2 numbers at a time, I will have 28 comparisons in all. Trying all combinations for the first number, you have 7. Trying all combinations for the second number nit including its comparison to the first number (because it will be redundant), you will have 6 comparisons an so on. Adding it all up, you have 7+6+5+4+3+2+1=28.

7 0

3 years ago

The answer for number 17

Sedbober [7]

Since cube has all faces as Squares

perimeter of each face P = 22.2
as we know perimeter of a square is P = 4 * ( Sides of a square )

let the sides of the square be 'x'

Hence , 22.2 = 4 * x

=> x = 22.2/4
=> x = 5.55

hence the edge's length is 5.55

Note : if the length from edge to edge is asked then

Length of the Diagonal for a cube =
$\sqrt{3} \times x$
Hence we get edge to edge length as

√3 * 5.55 = 9.612

4 0

3 years ago