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rewona [7]
3 years ago
9

3x² + 24 + 45=0 quadratic form

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0
3x the power of 2 followers
mylen [45]3 years ago
6 0

Answer:

x = {3, 5}

Step-by-step explanation:

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Elliott’s backyard is 4800 square feet. His dad is going to pave 15% of this area to use as a patio. How many square feet will b
Gennadij [26K]

Step-by-step explanation:

\frac{15}{100}  \times 4800 \: ft {}^{2}

15 \times 18

720 \: ft {}^{2}

the answer is B

3 0
3 years ago
5+5(x+4)<20 help me out thanks for the help
Korolek [52]
= 5+ (5x+20)<20
5x +25<20
5x< -5
x< -1
5 0
3 years ago
The energy usage of a light bulb is a function. The input for the function is _____ measured in hours.
Elena L [17]

Answer:

Time

Step-by-step explanation:

8 0
3 years ago
Calculate the pay for the following day of a
DiKsa [7]

9514 1404 393

Answer:

  $109.38

Step-by-step explanation:

The time worked was ...

  (12:00 -8:00) +(17:30 -12:45) = 4:00 + 4:45 = 8:45 . . . . hours:minutes

This is 8 45/60 hours = 8 3/4 hours = 8.75 hours.

The pay for 8.75 hours is ...

  8.75 × $12.50 = $109.375 ≈ $109.38

3 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
3 years ago
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