I think you mean "what is the QUOTIENT?"




Answer:
16m + 3n
Step-by-step explanation:
Combine like terms.
This answer is correct.
Hope this helps!
~Courtney
Answer: The number of rolls of paper is
.
Step-by-step explanation: Given that Andy is hanging wallpaper in his kitchen. 6 rolls of wallpaper is used to cover
of the walls.
We are to find the number of rolls of paper used per wall.
We will be using unitary method to solve the given problem.
We have,

Now, number of rolls used to cover
of the walls = 6.
Therefore, number of rolls used to cover 1 wall is given by

Thus,
rolls of paper used per wall.
Answer:

Step-by-step explanation:
Given



Required
Determine the length of AB
Because A'B'C'D is a dilation of ABCD, then the following relationship must exist:

Substitute values for A'B', B'C' and BC

Express the ratio as fractions:

Multiply through by 14





Answer:
12
Step-by-step explanation:
40/100*30
=12