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Ad libitum [116K]
2 years ago
7

Determine whether Rolle's Theorem can be applied to f on the closed interval [a, b]. (Select all that apply.)f(x) = 6 cos πx, [0

, 2]Yes, Rolle's Theorem can be applied.No, because f is not continuous on the closed interval [a, b].No, because f is not differentiable in the open interval (a, b).No, because f(a) ≠ f(b).If Rolle's theorem can be applied, find all values of c in the open interval (a, b) such that f '(c) = 0. (Enter your answers as a comma-separated list. If Rolle's Theorem cannot be applied, enter NA.)
Mathematics
1 answer:
andreev551 [17]2 years ago
7 0

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Find the volume of this square based pyramid. 5 cm 5 cm 5 cm. Round to the nearest tenth.
vodka [1.7K]

Answer:

41.666 cm³ or 41.7 cm³  rounded to the nearest tenth.

Step-by-step explanation:

Volume of a square pyramid = base length² × height ÷ 3

25 × 5/3 = 41. 666

Have a great day:)

4 0
3 years ago
Find a negative integer M so that the equation (x-12)(x+m) = m-51​
AleksAgata [21]

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Step-by-step explanation:

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8 0
3 years ago
The distance a spring will stretch varies directly with how much weight is attached to the spring. if a spring stretches 9 inche
Tcecarenko [31]
9/100 = x/90
Cross multiply to get 810 = 100x
Divide both sides by 100 to get x = 81 inches
6 0
3 years ago
Please help thanks!!
Lostsunrise [7]
Help with what there is nothing?
4 0
3 years ago
A rope 8 feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Find a functi
shtirl [24]
<span>1st piece: x feet
2nd piece: 8-x feet
--------------------------
Use the "x" piece to form a circle:
Circumference = "x".
2(pi)*radius = x

radius = x/(2pi)
So, Area = pi[x/(2)]^2 = x^2/(4pi) = (1/4pi)x^2
=========================================================
Use the 10-x piece to form square:
side = (1/4pi)(10-x)
Area = side^2 = (1/16)(10-x)^2

Hope this helps! :)</span>
8 0
3 years ago
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