Determine the equations of the vertical and horizontal asymptotes, if any, for f(x)=2x/x+4
1 answer:
ANSWER
Vertical asymptote: x=-4
Horizontal asymptote: y=2
EXPLANATION
The given equation is
The vertical asymptote is determined by equating the denominator to zero and solve for x.
The equation of the vertical asymptote is
The numerator has the same degree as the denominator.
The equation of the horizontal asymptote is the coefficient of the leading term in the numerator expressed over the coefficient of the leading term in the denominator.
y=2
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So, the answer is 4.5
4) (a) For these problems, you should take time to familiarize yourself with common fractions that appear on the unit circle. does not appear in the unit circle unless you take the quotient 1/2 divided by sqrt(3)/2 which gives you 1/sqrt(3) which is the same as sqrt(3)/3. So our numerator is 1/2 and our denominator is sqrt(3)/2.
And remember tangent is just sin/cos. So what degree has sinx as 1/2 and and cosx as sqrt(3)/2? Well, 30 degrees does, but 30 degrees is not within the range we are given. That means they are looking for a sinx that gives us -1/2 and a cosx that gives us -sqrt(3)/2 and that is 210 degrees.
And 210 degrees in radians is 7pi/6.
I hoped that made sense.
(b) This is a lot easier. What angle gives us a cos x of -sqrt(3)/2? According to the unit circle, 150 degrees and 210 degrees does. They usually want these in radians, so the answer is 5pi/6 and 7pi/6, respectively.
5) What quadrant is radian measure 5 in?
Well 2pi or roughly 6.28 is a full circle. And 5 is slightly less than 6.28, so it is probably in quadrant IV.
But to be sure let's change 5 radian to degrees:
5 * 180/pi = 900/pi = 286.48 degrees
286.48 degrees is definitely in Q4, so we are correct.