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Oduvanchick [21]
3 years ago
12

Give one example of the following properties for whole number under addition​

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0

Step-by-step explanation:

Objective: Recall the properties.

a) 3+1=4

b) 3+7=7+3

c) 3+(7+4)=7+(3+4)

d). 3(7+4)=(3×7)+(3×4)

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Which expression is equivalent to 3+2? 
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Answer:

Any expression that equals 5.

Step-by-step explanation:

3 + 2 = 5, so any expression that equals 5 is equivalent to 3+2.

8 0
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I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
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Answer:

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For 38 pieces we have price $406

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6 0
3 years ago
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Vitek1552 [10]
(-1.7, -4.9) 

to reflect across the x-axis multiply the x-value by negative 1

8 0
3 years ago
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