I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.
The median is a halfway point in the set of data.
List the numbers in order from smallest to largest:
111, 129, 144, 149, 152, 162, 166, 171
Because there are an even number of values in the data set, find the two middle numbers, add them together and then divide by 2:
Median = ( 149 + 152 ) /2
Median = 150.5
This is a normal distribution with a Mean: 14 g/dL and a Standard deviation: 1 g/dL.
A ) Hemoglobin levels less than 13:
13 = 14 - 1 = Mean - 1 SD
0.16 x 200 = 32
Answer: 32 people.
B ) Hemoglobin levels greater than 14 :
0.50 x 200 = 100
Answer: 100 people.
4/7 is the answer.
I cant reall explain becuase it will take forever xD