1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lorico [155]
3 years ago
13

Identify the benchmark you can use to find an equivalent percent for the ratio. Then find the equivalent percent.

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0
2/5 = 40%. 100 divided by 5 = 20 x 2 = 40%
You might be interested in
Hi my name is naomi am new here Does anyone know how I can find my best friend Dejenar in this app. Nice to meet u guys
stich3 [128]

Answer:

ask for her username

Step-by-step explanation:

6 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
Let a, b, and c be constants, and let x be a variable. Which of the following is
Nonamiya [84]

Answer:

C

Step-by-step explanation:

We have:

a(x+b)

Where a<0.

We would like to solve for a. So, let’s divide both sides by a.

Notice that a<0. Therefore, a is negative. Hence, we must flip the sign since we are dividing by a negative. This yields:

x+b>\frac{c}{a}

Now, we will subtract b from both sides. Therefore, our inequality is:

x>\frac{c}{a}-b

Hence, our answer is C.

5 0
3 years ago
PLEASE help me and PLEASE show the work PLEASE.
Dafna1 [17]

20(4×-2)

________

(4 - (-2))²

simplified;

20(-8)

_____

(6)²

simplified;

-160

______

36

simplified;

-4 16/36

simplified;

-4 4/9


3 0
3 years ago
Find the product. (10^2)^3 <br> 1,000 <br> 10,000 <br> 100,000 <br> 1,000,000
dangina [55]
The answer is 1000000
10^2=100
100^3=1000000
3 0
3 years ago
Other questions:
  • How many edges does a regular prism have?​
    5·2 answers
  • Nick has to build a brick wall. each row of the wall requires 6² bricks how many bricks will nick need to build the wall.
    13·1 answer
  • Suppose that circles A and B have a central angle measuring 75°. Additionally, circle A has a radius of 5 2 feet and the radius
    12·1 answer
  • When we say a function is increasing between two values. Which value are we looking at ?
    7·1 answer
  • 20 points and Brainliest to fastest correct answer!!
    11·1 answer
  • 60 POINTS PLEASE SEND ME A COMPLETED COPY OF THIS "linear functions worksheet: child's growth and prosperity
    13·2 answers
  • Can someone please help me with this!!! B
    5·2 answers
  • What are the common factors of 16 and 24?
    14·1 answer
  • Please help me asapppp<br><br> ty :)
    15·1 answer
  • Find the area of a circle with radius, r = 60cm. Give your answer rounded to 3 SF.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!