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saul85 [17]
3 years ago
15

Please help me! Thank you!

Mathematics
1 answer:
Mariana [72]3 years ago
4 0
The correct answer is D
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Who knows BAD BUNNY I AM watching him?
timurjin [86]
I do not sorry about that
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2 years ago
Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
3 years ago
find an equation in slope intercept form for the line though point P(-3,2) and perpendicular to the line containing the two poin
CaHeK987 [17]

Answer:

y=-1/5 x +7/5

Step-by-step explanation:

First lets find the slope of the line containing the points (2,3) and (1,-2) by using the equation for slopes m1 = (y2 - y1) / (x2 - x1),

Which results in m1=5

If two lines are perpendicular, then their slopes must satisfy the following condition

m1*m2=-1

So, our new line must have the following slope (m2): m2*m1=1, if m1=5, then m2=-1/5

The line passes through P(-3,2)

Remember that the equation for a line is given by the following:

y=mx+b

if we eval P inside that equation, with m=-1/5

we have b.

2=-1/5*-3 +b

b=2-3/5

5 0
3 years ago
Ron has 4 cartons of orange juice. He pours 1/6 of juice for everyone on camping trip. How many people did he serve?
Ronch [10]

Answer:

24 people

Step-by-step explanation:

3 0
2 years ago
What number is 20% of 199?
Vsevolod [243]
199/100 = 1.99

1.99*20 = 39.8

20% = 39.8
7 0
3 years ago
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