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3 years ago

Solve the equation 2sin x cos x = cos x, for 0° < x≤ 90°

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

2sinx.Cosx=cosx

2sin90°.cos90°=cos90°

2×1.0=0

0=0

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Anyone here good at algebra? if so PLEASE HELP MEH ;-;

vovangra [49]

I’ll tell y’all 4 if did

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3 years ago

What is 5 4/9 - 2 5/9

just olya [345]

Answer:

5 4/9 - 2 5/9= 26/9 or 2 8/9

Step-by-step explanation:

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2 years ago

Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

Help- erm...........

mash [69]

Answer:

00,000

Step-by-step explanation:

bc you times it all toghther

7 0

2 years ago

For f (x)= -x + 8, what is the value of x for which f(x) = 9?

Elina [12.6K]

Answer:

x=-1

Step-by-step explanation:

f (x)= -x + 8

Let f(x) = 9

9 = -x+8

Subtract 8 from each side

9-8 = -x+8-8

1 = -x

Multiply each side by -1

-1 = x

8 0

3 years ago

Solve the equation 2sin x cos x = cos x, for 0° < x≤ 90°​

Solve the equation 2sin x cos x = cos x, for 0° < x≤ 90°