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SIZIF [17.4K]
3 years ago
7

Solve the equation 2sin x cos x = cos x, for 0° < x≤ 90°​

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

2sinx.Cosx=cosx

2sin90°.cos90°=cos90°

2×1.0=0

0=0

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If you compare the red triangle to the blue triangle are the figures similar, congruent, neither, or it is impossible to tell?
bixtya [17]

Answer:

Congruent

Step-by-step explanation:

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given sin0= 2/3 and angle 0 is in quadrant 2, what is the exact value of cos0 in simplest form? simplify all radicals if needed
Kitty [74]

Answer: ( -\sqrt{5} / 3)

Step-by-step explanation:

sin(angle) = opposite/hypotenuse

opposite =2

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opposite^2 + adjacent^2 = hypotenuse^2

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adjacent^2 = 9 - 4

adjacent^2 = 5

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cosx = (adjacent/hypotenuse)

cosx = (-\sqrt{5}/3)

(-\sqrt{5}/3)

4 0
2 years ago
A tree is currently 8 feet tall and growing at a rate of 3 feet per year. How tall will the tree be in 12 years?
aleksandr82 [10.1K]

Answer:

44

Step-by-step explanation:

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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