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NARA [144]
3 years ago
11

Match the reasons with the statements in the proof if the last line of the proof is: 6. ∠3 and ∠5 are supplementary because of t

he definition of supplementary. Given: s | | t Prove: 3, 5 are supplementary
Mathematics
1 answer:
mote1985 [20]3 years ago
5 0

Answer with Step-by-step explanation:

We are given that

Line s is parallel to line t.

To prove that : angle 3 and angle 5 are supplementary.

1.s\parallelt

Reason: Given

2.Angle 1 and  angle 3 are supplementary

Reason: Exterior sides in opposite rays

3.\angle 1+\angle 3=180^{\circ}

Reason: By definition of supplementary

4.\angle 1=\angle 5

Reason: If lines are parallel , then corresponding angles are equal.

5.\angle 3+\angle 5=180^{\circ}

Reason: Substitution

Hence, proved.

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How many solutions does this nonlinear system of equations have?
joja [24]

Answer:

the answer is B. one (solution)

Step-by-step explanation:

hope it helps

mark me brainliest pls

4 0
3 years ago
An airplane, flying at an altitude of 6 miles, is on a flight path that goes directly over you. If θ is the angle of elevation,
wariber [46]

Answer:

Distance between the person and the plane is 12 miles

Step-by-step explanation:

From the figure attached,

An airplane is flying at an altitude AB = 6 miles.

An observer is standing at point C from where he observes the plane at an angle of elevation θ

Therefore, sinθ = \frac{\text{\text{Opposite side}}}{\text{Hypotenuse}}

sinθ = \frac{AB}{AC}

AC = \frac{AB}{sin\theta }

AC = 6cosecθ

If angle θ = 30°

Then AC = 6cosec30

AC = 6×2

AC = 12 miles

Therefore, distance between the person and the plane is 12 miles.

5 0
4 years ago
I need help with this question
bearhunter [10]

Answer:

  7.28 miles

Step-by-step explanation:

Suppose the distance at closest approach is represented by x. Then the distance to the point of closest approach at the first sighting is ...

  d1 = x·tan(62°)

At the second sighting, the distance to the point of closest approach is ...

  d2 = x·tan(38°)

The difference of these distances is 8 miles, so we have ...

  d1 -d2 = 8 = x(tan(62°) -tan(38°))

Dividing by the coefficient of x, we find ...

  x = 8/(tan(62°) -tan(38°)) ≈ 7.2764 . . . . miles

The point of closest approach is about 7.28 miles from the landmark.

5 0
3 years ago
A regression equation for this line is y = -0.42x + 19.26 a. What do the slope and y-intercept indicate? The slope indicates tha
qaws [65]

Answer:

B.The slope indicates that the percent is falling at about 0.4% each year. The y-intercept indicates the percent in 1985 should have been about 19%.

Step-by-step explanation:

A regression equation is it this form:

Y' = b0 + b1X

I am going to identify the slope and intercept in this equation to help us go further in our solution.

b1X is the slope. The slope usually has an x value multiplied to it

b0 is the intercept.

Back to our question, the equation in this question is

Y = -0.42X + 19.26

The slope is -0.42X.

The y intercept is 19.26

<em><u>The slope has a negative sign, this shows us that the percentage is falling by about 0.4% every year while an intercept of 19.26 tells us that percentage in 1985 should have been about 19%.</u></em>

I hope you found my solution useful?

8 0
4 years ago
Help :( plz plz plz plz plz plz
mylen [45]
16/81. I hope this helps

7 0
3 years ago
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