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Kaylis [27]
2 years ago
14

You have an equation y=x+7. Is the ordered pair (1,6) a solution? Yes or no?

Mathematics
1 answer:
vaieri [72.5K]2 years ago
8 0
Answer:
no

step-by-step explanation:
y=x+7
x is the slope of 1
7 is the y-intercept
because 7 is the y-intercept and the slope is positive it never touches (1,6)
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4y+20= 60 what does y equal?
lora16 [44]
Y=10 is the answer
I hope that helps
5 0
3 years ago
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How many terms are in this expression 3x2y4z − 6xy − 3z(5x2)
Liono4ka [1.6K]

Answer:C 3 Term

Step-by-step explanation:

8 0
3 years ago
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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
shusha [124]
Forces in direction x:
 
fx1 = 100 * cos (50) = 64.28
 fx2 = 50 * cos (160) = - 46.99
 The resultant is:
 fx = fx1 + fx2 = 17.29

 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
 fy2 = 50 * sine (160) = 17.10
 The resultant is:
 fy = fy1 + fy2 = 93.70
 The magnitude of the resulting force is:
 
f = root (fx ^ 2 + fy ^ 2)
 f = root ((17.29) ^ 2 + (93.70) ^ 2)
 f = 95.28
 The angle is:
 
theta = atan (fy / fx)
 theta = atan (93.70 / 17.29)
 theta = 79.55 degrees
 Answer:
 
The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
6 0
3 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
...........I need help......
ASHA 777 [7]

The anwer is B, f(x)=9500-750x

Hope this helps, brianliest if you can!

5 0
3 years ago
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