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7nadin3 [17]
3 years ago
15

Becky has already run 23 miles on her own, and she expects to run 1 mile during each

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

42

Step-by-step explanation:

Since Becky already ran 23 miles, and there is 1 mile per track practice, you add the 19 and 23 to get your answer.

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Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)
guapka [62]

Answer: 20

Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

\displaystyle \rm S_{\diamond}=6\cdot 5 =30 \\\\ S_{ABCD}=30-(5:2+5:2+5:2+3:2+1\cdot1)=30-(7,5+1,5+1)=\\\\30-10=20 \\\\ S_{ABCD}=20

4 0
3 years ago
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X < or = to 55 mph.
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5 0
3 years ago
Evaluate this exponential expression.
Levart [38]

Answer:

(-27)^\dfrac{2}{3} = 9

Step-by-step explanation:

Given that,

Asn expression : (-27)^\dfrac{2}{3}

We need to evaluate the above expression.

We know that, (-3)^3=-27

So,

(-27)^\dfrac{2}{3}=(-3)^{3\times \dfrac{2}{3}}

or

=(-3)^2\\\\=-3\times -3\\\\=9

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8 0
3 years ago
Solve the triangle. A = 54°, b = 11, c = 8
Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9 

Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
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3 years ago
PQR is a right-angled triangle.
ICE Princess25 [194]

Step-by-step explanation:

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3 years ago
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