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leva [86]
3 years ago
5

X +4=3.5=28 Need help

Mathematics
1 answer:
sattari [20]3 years ago
7 0

Answer: X=−0.5

Step-by-step explanation:

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10 cm same length as UT
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3 years ago
The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.
Bumek [7]
<h2>Answer:</h2>

<em><u>The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>

<h2>Step-by-step explanation:</h2>

In the question,

The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.

So,

Now we know that,

1 feet = 12 inches

So,

12 feet = 12 x 12 = 144 inches

So,

Total height of the vehicle which is permissible to pass under the bridge is,

12 feet 5 inches = 144 + 5 = 149 inches

Also,

Height of the truck = 162 inches

Therefore, we can see that the permissible height is smaller than the height of the vehicle.

Height of vehicle which is more than permissible height is by,

162 - 149 = 13 inches

<em><u>Therefore, the truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>

7 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
chubhunter [2.5K]

Answer:

\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is [1;+\infty[

f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2

x>=1 so x is positive and we can take the square root

so f^{-1}(x)=1+\sqrt{x}

8 0
3 years ago
A second bag of 40 marbles contains 11 red marbles, 9 blue marbles and 20 green marbles.
Goryan [66]

Answer:

Where is the first bag? We cant solve the question without knowing the marbles in the first bag

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME <br>2x+45=90<br>​
arsen [322]

Answer:

x = 45/2 = 22.5 cm

Step-by-step explanation:

2x + 45 = 90

2x = 90- 45= 45

2x = 45

x = 45/2 = 22.5 cm

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<em><u>hope</u></em><em><u> this</u></em><em><u> will</u></em><em><u> be</u></em><em><u> helpful</u></em><em><u> to</u></em><em><u> you</u></em> .

<em><u>if </u></em><em><u>you</u></em><em><u> find</u></em><em><u> it</u></em><em><u> useful</u></em><em><u>.</u></em>

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