Answer:
see explanation
Step-by-step explanation:
Differentiate using the product rule
Given y = f(x)g(x), then
= f(x). g'(x) + g(x). f'(x)
here f(x) = 
⇒ f'(x) =
g(x) = cosx ⇒ g'(x) = - sinx
Hence
= (- sinx) + cosx
= cosx - sinx
Answer:
2
Step-by-step explanation:
In all these expressions you have a power of a power.
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32
13) (q^10)^10 = q^(10×10) = q^100
15) (x^3)^-5 = x^[3×(-5)] = x^(-15)
17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5
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19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
