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oksian1 [2.3K]
3 years ago
9

Estimate 1.22Answer​

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0

Answer:

about 1

Step-by-step explanation:

Ksenya-84 [330]3 years ago
7 0

Answer:

if your asking to round to the nearest whole number than the answer is 1

Step-by-step explanation:

when nearing to the nearest [place number]

when the number is 5 or up, you round up!

when it is 4 or down, you round down!

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What is the common difference, d, in the arithmetic sequence defined by the formula below? an=2n+1
marishachu [46]
<h3><u>Answer:</u></h3>

  • d = 2

<h3><u>Solution:</u></h3>

We are given that the arithmetic progression is defined by :

➝ 2n + 1

<em>Therefore, </em>

  • <u>For </u><u>first </u><u>term</u>

➙ n = 1

➝ 2 × 1 + 1

➝ 2 + 1

➝ 3

  • <u>For </u><u>second </u><u>term</u>

➙ n = 2

➝ 2 × 2 + 1

➝ 4 + 1

➝ 5

  • <u>Common </u><u>difference</u>

➙ 2nd term - 1st term

➝ 5 - 3

➝ 2

<h3><u>More </u><u>information</u><u>:</u></h3>

  • The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.

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2 years ago
HELP!!!!!!!Choose the graph that matches the following system of equations:
PolarNik [594]
The last one. And I did answer for you too.

4 0
3 years ago
ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
  • cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
3 years ago
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